Question: #729

Lab 2 Maximum Range of a Projectile Complete Solution

Lab 2
Maximum Range of a Projectile: Due at the end of Week 2

All simulations can be downloaded here, this week's file name is "ATWOOD MACHINE.ip".

For Lab 2, please review Chapter 3 in your textbook. This lab involves a projectile being fired upward at an angle to the horizontal. You are to program the spreadsheet Excel (a similar substitute software program is permissible) to determine the maximum injection angle, that will result in the greatest downrange distance, R. Assume v = 10 m/s and g is approximated as g = 10 m/s2. Fill in the data table, and answers for the blanks and complete the graph (properly labeled and θmax annotated) in the Lab Answer Sheet at the end of this lab. {Hint: watch out for conversion problems from radians to degrees in Excel}.

Fill in the blanks in the Lab Answer Sheet at the end of this lab.
Submit this Lab Answer Sheet when all of the labs are completed.
These can be scanned and sent as pdf or picture files (e.g. tif, gif, etc.) or by any other method of your choice as long as the Answer Sheets are legible and translatable by Grantham University faculty.
Access Excel. Your data table will look similar to that found for Lab 2 below. The injection angle, θ will go from 0 degrees to 90 degrees in steps of two (2) degrees. Once you have the range formula programmed for θ = 0o use the “fill down” option in Excel to “distribute” the solutions to the other cells for the other angles. Include your completed full Excel data table with your Lab Answer Sheet. Then graph the data in order to construct a R. vs. θ graph. Denote on this graph, the maximum range, Rmax and the angle, θmax where this occurs. Be sure that your graph is properly labeled. For Lab 2 return your Lab Answer Sheet with: (1) completed Excel spreadsheet, and (2) graph of R vs. θ.

Solution: #743

Lab 2 Maximum Range of a Projectile Complete Solution

o (Degree) Range ,R (m)
0 0
2 0.048659656
4 0.19369152
6 0.432272712
8 0.759759519
10 1.169777784
12 1.654346968
14 2.204035483
16 2.808144266
18
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